CEILING
|
Number |
Raised Up |
|
|
2.1 |
3 |
=CEILING(C4,1) |
|
1.5 |
2 |
=CEILING(C5,1) |
|
1.9 |
2 |
=CEILING(C6,1) |
|
20 |
30 |
=CEILING(C7,30) |
|
25 |
30 |
=CEILING(C8,30) |
|
40 |
60 |
=CEILING(C9,30) |
What Does It Do?
This function rounds a number up to the nearest multiple
specified by the user.
Syntax
=CEILING(ValueToRound,MultipleToRoundUpTo)
The ValueToRound can be a cell address or a calculation.
Formatting
No special formatting is needed.
Example 1
The following table was used by a estate agent renting
holiday apartments.
The properties being rented are only available on a weekly
basis.
When the customer supplies the number of days required in
the property the =CEILING()
function rounds it up by a multiple of 7 to calculate the
number of full weeks to be billed.
|
Days Required |
Days To |
||
|
Customer 1 |
3 |
7 |
=CEILING(D28,7) |
|
Customer 2 |
4 |
7 |
=CEILING(D29,7) |
|
Customer 3 |
10 |
14 |
=CEILING(D30,7) |
Example 2
The following table was used by a builders merchant
delivering products to a construction site.
The merchant needs to hire trucks to move each product.
Each product needs a particular type of truck of a fixed
capacity.
Table 1 calculates the number of trucks required by dividing
the Units To Be Moved by the Capacity of the truck.
This results of the division are not whole numbers, and the
builder cannot hire just part of a truck.
|
Table 1 |
||||
|
Item |
Units To |
Truck |
Trucks |
|
|
Bricks |
1000 |
300 |
3.33 |
=D45/E45 |
|
Wood |
5000 |
600 |
8.33 |
=D46/E46 |
|
Cement |
2000 |
350 |
5.71 |
=D47/E47 |
Table 2 shows how the =CEILING() function has been used to
round up the result of
the division to a whole number, and thus given the exact
amount of trucks needed.
|
Table 2 |
||||
|
Item |
Units To |
Truck |
Trucks |
|
|
Bricks |
1000 |
300 |
4 |
=CEILING(D54/E54,1) |
|
Wood |
5000 |
600 |
9 |
=CEILING(D55/E55,1) |
|
Cement |
2000 |
350 |
6 |
=CEILING(D56/E56,1) |
Example 3
The following tables were used by a shopkeeper to calculate
the selling price of an item.
The shopkeeper buys products by the box.
The cost of the item is calculated by dividing the Box Cost
by the Box Quantity.
The shopkeeper always wants the price to end in 99 pence.
Table 1 shows how just a normal division results in varying
Item Costs.
|
Table 1 |
||||
|
Item |
Box Qnty |
Box Cost |
Cost Per Item |
|
|
Plugs |
11 |
£20 |
1.81818 |
=D69/C69 |
|
Sockets |
7 |
£18.25 |
2.60714 |
=D70/C70 |
|
Junctions |
5 |
£28.10 |
5.62000 |
=D71/C71 |
|
Adapters |
16 |
£28 |
1.75000 |
=D72/C72 |
Table 2 shows how the =CEILING() function has been used to
raise the Item Cost to
always end in 99 pence.
|
Table 2 |
||||
|
Item |
In Box |
Box Cost |
Cost Per Item |
Raised Cost |
|
Plugs |
11 |
£20 |
1.81818 |
1.99 |
|
Sockets |
7 |
£18.25 |
2.60714 |
2.99 |
|
Junctions |
5 |
£28.10 |
5.62000 |
5.99 |
|
Adapters |
16 |
£28 |
1.75000 |
1.99 |
|
=INT(E83)+CEILING(MOD(E83,1),0.99) |
Explanation
=INT(E83) Calculates
the integer part of the price.
=MOD(E83,1) Calculates
the decimal part of the price.
=CEILING(MOD(E83),0.99) Raises
the decimal to 0.99
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